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7p^2-15p=-8
We move all terms to the left:
7p^2-15p-(-8)=0
We add all the numbers together, and all the variables
7p^2-15p+8=0
a = 7; b = -15; c = +8;
Δ = b2-4ac
Δ = -152-4·7·8
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-1}{2*7}=\frac{14}{14} =1 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+1}{2*7}=\frac{16}{14} =1+1/7 $
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